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From Boundary Layers to Dissolution: Modeling Polymer Removal by a Flowing Solvent

15 min read

Problem adapted from Welty et al., Fundamentals of momentum, heat and mass transfer, 7th edition, problem 28.7.

Sketches were made using draw.io.
Plots were constructed using MATLAB.


Motivation

I enjoy applying transport modeling to small-scale processes with industrial applications, especially in manufacturing. I chose this problem because it demonstrates concepts such as boundary layers, convective mass transfer, and quasi-steady-state assumptions by applying them to a process that could realistically occur in manufacturing. This problem, adapted from Welty et al.’s Fundamentals of Momentum, Heat, and Mass Transfer, was a particularly interesting example.

I initially encountered the problem while preparing for my mass transfer final. What intrigued me was that the polymer film does not dissolve uniformly, and that we can model its thickness as a function of both position and time, h(x,t)h(x,t), to predict how its shape changes as it dissolves.

I found the problem interesting enough that I wanted to extend the solution beyond what the original problem statement required. In addition to solving the model, I decided to examine its assumptions and limitations and provide a visual walkthrough of the modeling procedure.

Problem statement

The system consists of a thin polymer film deposited on a flat surface and exposed to flowing MEK, which acts as a solvent for the polymer. As the liquid travels over the surface, polymer dissolves into the MEK and is carried downstream.

Because the concentration boundary layer grows along the direction of flow, the mass-transfer coefficient, and therefore the dissolution rate, is not constant over the surface. The goal of this analysis is to quantify this behavior using boundary-layer mass-transfer correlations and explore how it leads to a nonuniform polymer thickness as dissolution proceeds.

Figure 1: Sketch of the problem showing the nomenclature and important physical phenomena.
The blue curve is a representation of the hydrodynamic boundary layer. The actual scales are discussed later.
The top of the fluid is unbounded.

Designating polymer as A and MEK as B :

NA,y:N_{A,y}: mass flux of polymer [gcm2.s][\frac {g}{cm^2.s}] .

CA:C_{A \infin}: Concentration of polymer in the bulk fluid [gcm3][\frac {g}{cm^3}].

CAs:C_{As}: Concentration of polymer at the surface (saturation concentration) [gcm3][\frac {g}{cm^3}].

kx:k_{x}: local mass transfer coefficient [cms][\frac {cm}{s}].

ρs:\rho_s: density of the solid polymer [gcm3][\frac {g}{cm^3}].

Modeling

Model goal: Model should be able to predict the thickness of the polymer film at any specified location and time i.e,h(x,t)h(x,t). It should also be able to predict the overall shape of the film over time as liquid solvent flows over it.

Assumptions :

  1. Hydrodynamic boundary layer’s thickness and shape do not change significantly as the polymer is dissolved.
  2. Laminar flow over the entire film length.
  3. Saturation concentration at the polymer-solvent interface is constant throughout the dissolution. i.e, CAs=constantC_{As}=constant.
  4. Concentration of polymer in the bulk fluid is negligible and approximated as zero and constant. CA0C_{A \infin} \approx 0. In reality however, polymer diffuses through the concentration boundary layer into the bulk fluid.
  5. Density of the solid polymer is assumed constant. This means MEK diffusion into the polymer matrix and any resulting swelling are neglected. i.e, ρs=constant\rho_s= constant.
  6. Bulk fluid properties remain constant. νB\nu_B, ρB\rho_B, etc

The flux equation in terms of mass transfer coefficient is:

NA,y(x,t)=kx(x,t)[CA,s(t)CA(t)](1){N_{A,y}(x,t)=k_{x}(x,t)[C_{A,s}(t)-C_{A \infin }(t)]} \tag{1}

Under the assumption that the hydrodynamic and concentration boundary layers are quasi-steady, their time dependencies can be neglected.

NA,y(x)=kx(x)(CA,sCA)(2)\boxed {N_{A,y}(x)=k_{x}(x)(C_{A,s}-C_{A \infin })} \tag{2}

Here, assumptions 1, 3 and 4 were used. Under these assumptions, since the mass transfer coefficient is a function of distance from the leading edge (i.e, xx), so is the mass flux. In other words, NA,yN_{A,y} is a function of xx because the concentration boundary layer grows in that direction.

hh (thickness of the film) is a function of time and position, i.e, h=h(x,t)h=h(x,t). It depends on position because mass transfer flux is a function of xx and hh is related to mass transfer flux as discussed later.

h=f(NA,y(x),t)=g(x,t)(3)h=f(N_{A,y}(x),t)=g(x,t) \tag{3}

To find the relationship between hh and tt, let’s consider a small element in the xx direction, with length Δx\Delta x at distance xx from the leading edge. Δx\Delta x must be so small that mass flux (NA,y)(N_{A,y}) can be approximated as constant across the element. Figure 2 shows the element and the 3D shape of the polymer film. This way, we temporarily treat xx as fixed, and can focus on the relationship between hh and tt at a given local mass flux.

Figure 2: The 2D and 3D sketch of the polymer film

To do this, we write mass balance for the polymer in the element:

Accumulation=Input  Output + Generation  Consumption(4)Accumulation=Input \ - \ Output \ + \ Generation \ - \ Consumption \tag{4}

Let’s discuss each term:

  • Input:Input: Zero. Polymer isn’t being added to the element.
  • Output:NA,y×As=NA,y×Δx×WOutput: N_{A,y} \times A_s = N_{A,y} \times \Delta x \times W
  • GenerationGeneration and Consumption:Consumption: Zero since we have no reactions taking place inside the element.
  • Accumulation:Accumulation: Not zero since the polymer is clearly being dissolved.
Accumulation=dmAdt=d(ρs×W×h(x,t)×Δx)dtAccumulation =\frac {dm_A}{dt}= \frac {d(\rho_s \times W \times h(x,t) \times \Delta x)}{dt}

Mass balance becomes :

d(ρs×W×h(x,t)×Δx)dt=NA,y×Δx×W\frac {d(\rho_s \times W \times h(x,t) \times \Delta x)}{dt} =-N_{A,y} \times \Delta x \times W

Eliminating WW and Δx\Delta x :

ρsdh(x,t)dt=NA,y\rho_s\frac {dh(x,t)}{dt} =-N_{A,y}

It might be tempting to say that since we eliminated Δx\Delta x, h h does not depend on position. However, it does depend on NA,yN_{A,y}, which is a function of xx.

So I would like to remind you that his relation is actually:

ρsdh(x,t)dt=NA,y(x)\rho_s\frac {dh(x,t)}{dt} =-N_{A,y}(x)

set at a fixed and known xx. Because we assumed that NA,yN_{A,y} is independent of time, the derivative dhdt\frac {dh}{dt} is constant at a given xx. Therefore at a given xx, film thickness (h)(h) varies linearly with time.

Integrating with initial condition h(x,0)=0.02 cmh(x,0)=0.02 \ cm :

h(x,t)=NA,y(x)ρst + h(x,0)(5a)\boxed {h(x,t)=- \frac {N_{A,y}(x)}{\rho_s}t \ + \ h(x,0)}\tag{5a}

Subject to the constraint:

h(x,t)0(5b)\boxed{h(x,t) \geq 0} \tag{5b}

As expected, a higher NA,yN_{A,y} (mass transfer flux) means a more negative slope, causing the polymer thickness to decrease more rapidly.


NA,y(x)N_{A,y}(x) term:

Now that we know how thickness changes with time at a given xx, we will turn our attention to how mass flux (NA,y)(N_{A,y}) changes with position.

Mass flux at a given xx is a function of the concentration gradient at the surface:

NA,y(x)=DABCAy(x)y=0(6)N_{A,y}(x)= -D_{AB} \frac {\partial C_A}{\partial y}(x) \bigg|_{y=0} \tag{6}

The gradient term is inconvenient to find, since we don’t know the exact concentration profile in the boundary layer, CA(x,y)C_A(x,y).

The mass transfer coefficient approach is more convenient.

NA,y(x)=kx(x)[CAsCA](7)N_{A,y}(x)=k_{x}(x)[C_{As}-C_{A\infin}] \tag{7}

Since CA,sC_{A,s} and CAC_{A \infin} are assumed constant, the problem is now to find the local mass transfer coefficient as a function of xx.

To calculate the mass transfer coefficient, we introduce the Sherwood number:

Shx=kx(x)xDAB(8a)Sh_x=\frac {k_{x}(x)x}{D_{AB}} \tag{8a} k(x)=DABShxx(8b)\boxed {k(x)=\frac {D_{AB}Sh_x}{x}}\tag{8b}

Now sherwood number is related to other dimensionless numbers. RexRe_x and ScSc that represent the hydrodynamics and fluid properties respectively.

Shx=f(Rex,Sc)(9)Sh_x=f(Re_x,Sc)\tag{9}

RexRe_x (Reynolds number) and ScSc (Schmidt number) are defined as:

Sc=νDAB(10)Sc=\frac {\nu}{D_{AB}}\tag{10} Rex=U xν(11)Re_x=\frac {U _\infin \ x}{\nu}\tag{11}

The function ff is usually determined experimentally by fitting appropriate constants to the general equation :

Shx=aRexbScc(12)Sh_x=aRe_x^bSc^c\tag{12}

Laminar boundary layer verification :

Since RexRe_x increases with xx, its maximum will occur at the end of the polymer film.

ReL=ULνB(13)Re_L=\frac {U_\infin L}{\nu_B} \tag{13}

Substitution yields:

ReL=1.5 [cms]×20 [cm]6×103 [cm2s]=5000Re_L= \frac {1.5 \ [\frac{cm}{s}]\times20 \ [cm]}{6\times 10^{-3} \ [\frac{cm^2}{s}]} = 5000

Which is in laminar flow range for a flat plate.

For laminar flow over a flat plate, a semi empirical Sherwood correlation is used:

Shx=0.332Rex12Sc13(14a)Sh_x=0.332 Re_x^{\frac {1}{2}} Sc^{\frac{1}{3}} \tag{14a} ReL<2×105(14b)Re_L<2 \times 10^5\tag{14b} Shx=0.332 (Uxν)12Sc13(14c)Sh_x=0.332 \ (\frac{U_\infin x}{\nu})^{\frac {1}{2}} Sc^{\frac {1}{3}}\tag{14c}

We will keep Schmidt number in dimensionless form.

Substitution yields:

k(x)=DAB×0.332 U12 Sc13x12ν12(15)\boxed{k(x)=\frac {D_{AB}\times 0.332 \ U_\infin^{\frac{1}{2}} \ Sc^{\frac{1}{3}} }{x^{\frac{1}{2}}\nu^{\frac{1}{2}}}}\tag{15}

Now that we have k(x)k(x), we can substitute to calculate the flux NA,y(x)N_{A,y}(x):

NA,y(x)=DAB×0.332 U12 Sc13x12ν12[CAsCA](16)\boxed{ N_{A,y}(x)=\frac {D_{AB}\times 0.332 \ U_\infin^{\frac{1}{2}} \ Sc^{\frac{1}{3}} }{x^{\frac{1}{2}}\nu^{\frac{1}{2}}}[C_{As}-C_{A\infin}]}\tag{16}

Now we know the flux at every xx. Note as we increase the distance from the leading edge, the flux decreases:

NA,yx12(17)N_{A,y} \propto {x^{-\frac{1}{2}}}\tag{17}

Under our assumptions, to predict the shape of the polymer as it dissolves, we need to calculate the height of the polymer at every xx, at a fixed time.

Remembering our assumptions that NA,yN_{A,y} is independent of time and the concentration and hydrodynamic boundary layers won’t undergo significant change, its convenient to calculate the flux on the entire xx grid and then use equation (5a) and (5b) to calculate the thickness.


Results

The thickness of the plate was calculated after 1,5,10,50 and 100 minutes.

To put the scales into perspective, lets compare the thicknesses of the film with boundary layers and channel height (which is 2 cm tall)

Recalling Blasius solution of boundary layer thickness:

δh=5xRex(18)\delta_h=\frac {5x}{\sqrt{Re_x}} \tag{18}

The Schmidt number term (with exponent) is approximately the ratio of hydrodynamic and concentration boundary layers:

δcδhSc13(19)\delta_c \approx \frac {\delta_h}{Sc^\frac{1}{3}}\tag{19}

Plotting yields:

Figure 4: Comparison of the hydrodynamic and concentration boundary layers with the polymer film.
Note that the hydrodynamic boundary layer and channel height are orders of magnitude thicker than the polymer film.

Discussion

The profiles calculated in Figure 3 reflect the effect of boundary layer growth and the subsequent decrease in mass-transfer flux in the xx direction.

The mass transfer flux, and therefore the local dissolution rate, decreases monotonically in the xx direction, following

NA,yx1/2(17)N_{A,y}\propto x^{-1/2}\tag{17}

Therefore, at a given time, we expect the polymer thickness to be smaller as we get closer to the leading edge. This behavior can be seen in the calculated profiles in Figure 3.


Shifting of the Leading Edge

Near the leading edge, the polymer dissolves faster. As more and more of the film is dissolved, a region where the polymer thickness is zero begins to form near the original leading edge.

We can define the position of the remaining polymer by a moving location xl(t)x_l(t), where

h(xl(t),t)=0(20)h(x_l(t),t)=0\tag{20}

and the polymer thickness becomes nonzero immediately downstream of this point.

You can think of xl(t)x_l(t) as a new effective leading edge for the remaining polymer. In other words, it is as if the origin used for the mass-transfer boundary layer is gradually shifting towards the right as the upstream part of the film disappears.

This means that the original concentration boundary layer can no longer be assumed to remain unchanged after local depletion begins. Instead, the concentration boundary layer over the remaining polymer would have to redevelop from approximately the new leading edge.

If the distance from this new leading edge is written as

x=xxl(t)(21)x^′=x−x_l(t)\tag{21}

then the local mass-transfer coefficient would depend on xx', rather than the original distance from x=0x=0.

This model does not account for this shift. It calculates the mass transfer flux based on the original leading edge and simply applies the constraint:

h(x,t)0.(5b)h(x,t)≥0.\tag{5b}

Therefore, after part of the polymer film has completely dissolved, the calculated profile should be considered an approximation rather than a fully accurate description of the physical system.

(In the future, this model will be further modified to take this effect into account)


Validity of the Quasi-Steady Assumption

One of the main assumptions of this model was that the hydrodynamic and concentration boundary layers do not change significantly with time. This allowed us to treat the mass transfer flux as constant during the dissolution

This assumption can be justified by comparing the timescale of boundary-layer development with the timescale of polymer dissolution. The flow and concentration fields develop relatively quickly after the solvent starts flowing, while the polymer film requires a much longer time to undergo a noticeable change in thickness.

Therefore, if

tboundary layertdissolutiont_{\text{boundary layer}} \ll t_{\text{dissolution}}

the boundary layers can be approximated as reaching their steady profiles almost instantaneously compared with the rate at which the polymer surface changes.

In this case, the polymer thickness is still changing with time, but the transport process at each instant can be approximated using a steady boundary layer. This is the basis of the quasi-steady approximation used in the model.


Effect of Polymer Thickness on the Boundary Layer

Another assumption was that the dissolution of the polymer does not significantly change the hydrodynamic or concentration boundary layers.

Figure 4 compares the polymer thickness with the thicknesses of the hydrodynamic and concentration boundary layers. The polymer film is much thinner than the hydrodynamic boundary layer, and its change in thickness during dissolution is also small compared with the overall dimensions of the flow.

Approximating the hydrodynamic boundary layer as unchanged during dissolution appears reasonable within the conditions considered here since this suggests that the recession of the polymer surface may have only a small effect on the general flow field.

If the polymer layer were much thicker, changes in the surface position could have a larger effect on the velocity and concentration fields.


Effect of Finite Liquid Depth

The Sherwood-number correlation used in this model is based on boundary-layer development over a flat plate. However, in this problem, the liquid has a finite depth and a free surface.

Figure 4 compares the hydrodynamic boundary layer thickness with the liquid depth.

Near the leading edge, the boundary layer is much thinner than the liquid depth, so the flat-plate approximation seems reasonable. As xx increases, however, the boundary layer becomes thicker and takes up a larger portion of the liquid depth.

If the boundary layer becomes comparable to the liquid depth, there may no longer be a clear free stream region above it. In that case, the flat-plate correlation may become less accurate farther downstream.

For example if the film was long enough so that at one point δh(xc)2 cm\delta _h (x_c) \approx 2 \ cm (the depth of the liquid in channel), the flat plate assumption will effectively break down for x>xcx>x_c .

Therefore, satisfying the ReL<2×105Re_L<2\times 10^5 condition for laminar flow alone does not necessarily mean that the flat-plate correlation is valid over the entire length.


Negligible Polymer Concentration in the Bulk Fluid

In the model, the polymer concentration in the bulk fluid was assumed to be negligible. This makes the mass-transfer driving force approximately

CA,sCA,CA,sC_{A,s}-C_{A,\infty}\approx C_{A,s}

In reality, however, polymer continuously dissolves into the solvent and is carried downstream. Therefore, the polymer concentration in the bulk fluid may gradually increase in the xx direction.

If this increase becomes significant, the concentration difference between the polymer surface and the bulk fluid will decrease downstream. This would reduce the mass-transfer flux even further than what is predicted only from boundary-layer growth.

A more complete model could replace the constant CA,C_{A,\infty} with a bulk concentration CA,b(x)C_{A,b}(x) and include a mass balance on the flowing solvent.

For the current model, CA0C_{A\infin} \approx 0 can be viewed as an approximation. This is more reasonable when the solvent flow rate is sufficiently large compared with the amount of polymer being dissolved.


Behavior Very Close to the Leading Edge

From the flat-plate correlation used in this model,

NA,yx1/2N_{A,y}\propto x^{-1/2}

Therefore,

NA,yasx0.N_{A,y}\rightarrow\infty \qquad \text{as} \qquad x\rightarrow0.

Obviously, an infinite mass-transfer flux cannot occur physically. This behavior results from the mathematical form of the local flat plate boundary layer correlation near the leading edge.

Therefore, predictions extremely close to x=0x=0 should be interpreted carefully. In practice, the geometry of the real leading edge and other transport effects would prevent the flux from becoming infinite.

This limitation is especially important in this problem because the model predicts the fastest dissolution close to the leading edge.


Constant Surface Concentration and Polymer Swelling

The model also assumes that the polymer concentration at the polymer-solvent interface remains at a constant saturation concentration,

CA,s=constantC_{A,s}=\text{constant}

and that the density of the solid polymer remains constant during dissolution. Diffusion of MEK into the polymer and any resulting swelling are therefore neglected.

These assumptions simplify the dissolution process to mass transfer from a well-defined polymer surface into the solvent.

A real polymer-solvent system can be more complicated. MEK may penetrate into the polymer before dissolution takes place, potentially causing swelling and changing the structure of the polymer near the interface. In that case, dissolution may not be represented only by the recession of a sharp surface.

The current model therefore represents a simplified, mass-transfer-controlled description of the dissolution process. A more detailed model could include solvent diffusion into the polymer and changes in the polymer properties during dissolution.

Conclusion

In this problem, a local mass balance was combined with a flat-plate mass-transfer correlation to model the polymer thickness as a function of both position and time, h(x,t)h(x,t).

Under the assumptions made in the model, the mass-transfer flux decreases with distance from the leading edge, following NA,yx1/2.N_{A,y}\propto x^{-1/2}. As a result, the polymer dissolves faster near the leading edge and the film does not remain uniform as dissolution continues. This behavior can be seen in the calculated thickness profiles.

The model gives a relatively simple way to connect boundary-layer growth with the changing shape of the polymer film. However, it is still an approximation. Once part of the polymer completely dissolves, the effective leading edge begins to shift and the concentration boundary layer would have to redevelop from the new surface. The current model does not account for this effect. Other assumptions, such as negligible polymer concentration in the bulk fluid, constant surface concentration, and neglecting polymer swelling, may also become important in a real polymer-solvent system.

For me, the most interesting part of this problem was seeing how a relatively simple mass-transfer correlation could be used to predict the changing shape of a dissolving film, while also seeing where the assumptions behind that model begin to break down.